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We figured out that the red triangle must be zero because a number multiplied by another number that equals the first number has to be zero; (a x b = a). then we found out that the pink square has to be 2. we know this as if we did 3×3 which equals nine then 3×9 equals 27 which is greater than 12 but 2×2 = 4 and 2×4 = 8 which is the only answer that it can be. So the orange oval is 4 and the yellow semi circle is 8. Then using our knowledge that the orange oval was 4, we thought about what the blue rectangle was. It can be 2,1 or 4 as they are already taken or wouldnt work, so it must be 3. Anything more would be too high. This means that the red circle is 12 and the green star is 9. Then on question E we thought what multiplied by 2 equals 12. So the green triangle is six. For equation H the yellow parrolellogram must be 1 (a x b=b). This equation links to equation G and we thought that if the purple star was 5 and the blue hexagon was 10 this would work in the equation. In conclusion the yellow parolellogram is 1, the pink square is 2, the blue rectangle is 3, the orange oval is 4, the purple star is 5, the green triangle is 6, the yellow semicircle is 8, the green star is 9, the blue hexagon is 10 and the red circle is 12.