ð™Žð™ð™¤ð™§ð™© ð™–ð™£ð™¨ð™¬ð™šð™§: ð™„ð™› ð™žð™© ð™žð™¨ ð™žð™£ ð™©ð™ð™š ð™›ð™¤ð™§ð™¢ ð™¤ð™› ð™ð™® / (ð™)(5^ð™˜)(2^ð™™) ð™žð™© ð™žð™¨ ð™©ð™šð™§ð™¢ð™žð™£ð™–ð™©ð™žð™£ð™œ.
ð™€ð™ð™¥ð™¡ð™–ð™£ð™–ð™©ð™žð™¤ð™£:We can say that all fractions in the form of y / 2^n (where y is any number) are terminating because 2^n x 5^n = 10^n and 10^n is terminating when divided by 100 (because it would just displace the number by 2 digits behind eg. 10^1 / 100 = 0.1), and using this same logic y / 5^n is terminating. Is that the answer? No!
1 / 50 is terminating but 50 ≠2 ^ n and 50 ≠5 ^ n.You can write this as y / (10^x / 2^n).This is equal to y / (5^n)(2^x). In fact y / 5^a = y / (5^c)(2^d) and y / (5^c)(2^d) = y / 2^b , because x^0 = 1. Is that the answer?
No!
3/150 is terminating but isn't in the form of y / (5^c)(2^d).It is terminating because it simplifies into 1/50 which is in the form of y / (5^c)(2^d).So we can write the answer as xy / (x)(5^c)(2^d).