Solution

Hunting for Averages Jason Chen Jason Luo Justin Martin Adyuth Xander Nathan Raphael Leya

First name
Jason Chen, Jason Luo, Justin, Martin, Adyuth, Xander, Nathan, Raphael, Leya
School
ESF Clearwater Bay School
Country
Age
7

We worked as a group to solve the problem. 

 

1st - 6

9+ 11+4 + 0 = 24

24 ÷ 4 = 6

 

2nd - 5

10 + 5 + 8 = (23 + ___ ) ÷ 4 = 7

7 x 4 - 8 - 10 = 5

 

3rd - 9, 7

20 + 7 + 2 = 29

29 + 7 = 36 (We thought what could be the closest multiple of 4)

36 ÷ 4 = 9

15+ 3 + 1 + 9 = 28

28 ÷ 4 = 7

 

4th - 4, 6

9 + 3 + 8 = 20

20 + 4 = 24 (We thought what could be the closest multiple of 4)

24 ÷ 4 = 6

1+ 1 + 8 + 6 = 16

16 ÷ 4 = 4