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a) Perimeter Challenge
.Ask yourself what do you know about the problem.
.By asking yourself what you know about the problem you can figure out that the smaller diagram has been repeated twice in the larger diagram.In Addition to that the larger diagram has one length which is equal to 7 (33-(2x13)=33-26=7cm)
In the small diagram with have 2 widths and one length.The total height of the small diagram is 13 cm.7cm is for the length and the remaining 6cm is for the 2 widths.Therefore the width of the rectangle is 3cm.
So the perimeter of the small rectangle is 2 lengths=2x7+2x3=14+6=20cm.