24360

Every odd number which is of the form 2n+1 can be written as sum of n & n+1 which are also consecutive.

If it is an odd multiple of 3, say 3(2n+1), then 6n+3= 2n + (2n+1) + (2n+2).

If 'n' is even , NOT A MULTIPLE OF 3:-
Only in the case of an even number(which is also not a multiple of 3) there are 2 or more consecutive numbers to be added. Say 2(2n+1) = 4n + 2 = (n-1) + n +
(n+1) + (n+2)

If 'n' is even , A MULTIPLE OF 3:-
If it is an even multiple of 3, for eg 2(3n), then it will have more than 2 consecutive numbers for addition. 6n = 2n-1 + 2n + 2n+1