196159

The area formula goes like this : A=p/2+Inner points-1. THe way I founded out this formula is trying with the easiest shape which is the square and a isosceles with an area of 1cm(square),and an area of 3/2cm(square). I founded out for easy shapes you can minus the boundary dots(perimeter) by the inner dots, however it doesn't work on irregular shapes, so I evaluated it. The relationship between each of the 3 variables (area, perimeter and the inner dots) must contain 2 variables in the formula, so if I have a p=3, I=1, A=3/2 shape, what are the connections between eachother? A=3/2, the denominator might be useful in the formula, so I kept it. Seeing that the numerator has the same number of the perimeter, I added it in, so it looks like A=p/2???... Back to the square shape, if the p=4, I=0, A=1, A definetly is NOT 1/2, remembering that I said one variable's formula must contain the two other variables in this situation, if I add the inner dot(s) "I", in my triangle, A=p/2+1or-1, but reminding that in the square I have to minus a 1 to get to my area, I chose A=p/2+I-1,so now two variables are in the formula and I added a '-1' to make the formula happen.