Solution

196098

Problem / game
First name
Arjun
School
Canadian International School
Country
Age
12

The table in the image shows different possibilities of what the letters could be. So then if O=4 then R=8 as shown in the table above. So then you have to read it column wise so then you can understand it. F=1 will always stay the same because the numbers up to nine only add up to 19 max with a carry over and that’s. So then F=1 will always stay the same. I first tried out different values for the letter O and realised that O cannot be 1 and has to be above three because F is already one so then it will be the same. And then it has to be above then 3 because if O is equal to two or then there won’t be any values for the letters W and U because if W is five or bigger then it will carry over and then when you add the two T’s together then it would be odd and not even which would not be equal to O. For O=3 then it would mean repeating values which won’t work so then when I tried O=4 then it worked and then so on until 8 where 0=9 it gives repeating values for O and T since adding the two T’s together will need a carry over for O to be 9 which means that the letter T will also be 9 which again won’t work.