Problem / game
First name
Imeth Sanumitha
School
Pristine Private School , Dubai
School's Twitter handle
https://x.com/PristineSchool?s=20
Country
Age
11
Filename
For the four digits, the only possible 3 consecutive numbers which don't have three and can make a sum that is neither 3 nor one of the others, is 4,5,6. The Third digit of the 4-digit is 9. For the five digit, 5 does not work, as 5*3=15 which has a 5 in the last digit. But 4 and 6 do work, and give 2 and 8 respectively. But both carry a 1, and 1 + 3 * 9 = 28, with an 8. So the last two digits of the two numbers, for 4-digit and 5-digit respectively, are 9 4, and 8 2. For the First 2 digits of 4-digit, they can be 6 5 or 5 6. Using trial and error, only 5 6 works, and the numbers are: 5694 and 17082.