We realised that anything times the isosceles triangle equaled the isosceles triangle, so it must be 0. Then we figured out that the only cubed number below 12 was 2 because 1 would make it be another square as the answer, when it was a half-circle. That made the half-circle have a value of 8. We knew that something times 2 equaled 8 so we then realised that the oval must be 4. Next, we did the rectangle times rectangle and worked out that it was 3 because the only number squared that we could use was 3, as we had already used 2. After that, we did the rectangle times square which made the equilateral triangle equal 6. Then, we did the equilateral triangle times the square which made the circle 12. We then realised that the 8-pointed star must be 9 because 3 times 3 made 9. We saw that the rectangle times diamond equaled rectangle, so the diamond was 1. We then worked out the hexagon because the square times anything would be an even number ,and the only one we had left was 10. That made the 5-pointed star equal 5. The two numbers that had nothing to represent were 7 and 11.
Solution
159847
Problem
First name
Szymon, Charlie and Hattie
School
Edward Bryant School
Country
Age
11