Solution

154372

Problem / game
First name
Amrit Cassim
School
Hymers College
Age
14

solution to g)
1 sqrt(a)+sqrt(b)=sqrt(a+b+sqrt(4ab))
2 Squaring both sides
3 a+2sqrt(ab)+b=a+b+sqrt(4ab)
4 the sqrt of 4ab is 2sqrt(ab)
5 substituting this identity in
6 a+2sqrt(ab)+b= a+2sqrt(ab)+b
7 sqrt(a)+sqrt(b)=sqrt(a+b+sqrt(4ab)) is valid for all positive values of a and b