This is an observation
We found a pattern recurring in the two sequences
Sequence 1: T(n)=8n
Sequence 2: T(n)=4n2 +4 [4n(n+1)]
The first few terms of the sequence 1 are 8,16,24,32,40,48,56,64,72,80…
The first few terms of the sequence 2 are 8,24,48,80,120.
We realised that the first two numbers are the same and in the first sequence the 3rd number is the same as the 2nd. The 6th was the same as the 3rd. Every time sequence 1 skips one number then two, three etc. to get the next number in sequence 2.
The difference between the two sequences is 4n(n-1)
For the other two shapes we also got the sequences
Sequence 1: T(n)=6n+2
Sequence 2: T(n)=2n2+4n+2
The first few terms of the sequence 1 are 8,14,20,26,32,38
The first few terms of the sequence 2 are 8,18,32,50,72.
For this one we calculated the difference and its 2n2 -2n. These two sequences have to be related to the other two since the difference for this one half from the first.