# Pair Products

*Pair Products printable worksheet*

Choose four consecutive whole numbers.

Multiply the first and last numbers together.

Multiply the middle pair together.

Choose several different sets of four consecutive whole numbers and do the same.

What do you notice?

Can you explain what you have noticed? Will it always happen?

Click below to see how Charlie and Alison explained what they noticed.

**Charlie said:**

I can explain this by labelling the four consecutive numbers $n, n+1, n+2, n+3$.

Outer pair: $n(n+3) = n^2 + 3n$

Inner pair: $(n+1)(n+2) = n^2 + 3n + 2$

**Alison said:**

I drew a diagram, in which the product of each pair is represented by the area of a rectangle:

The outer pair is represented by the red rectangle.

The inner pair is represented by the blue rectangle.

The purple area is common to both.

The area of the red strip will always be two units less than the area of the blue strip.

Therefore, the product of the outer pair is always two less than the product of the inner pair.

Instead of doing lots of calculations, can you use these representations to compare the product of the first and last numbers with the product of the second and penultimate numbers, when you have:

- $5$ consecutive whole numbers

- $6, 7, 8, \ldots x$ consecutive whole numbers

- $4$ consecutive even numbers

- $4$ consecutive odd numbers

- $5, 6, 7, 8, \ldots x$ consecutive even or odd numbers

- $4$ consecutive multiples of $3, 4, 5 \ldots $

- Decimals that differ by $1$, such as $1.2, 2.2, 3.2, 4.2$

- Four numbers going up in $3$s, such as $2, 5, 8, 11$

- Four numbers going up in $\frac{1}{2}$s, such as $4, 4\frac{1}{2}, 5, 5\frac{1}{2}$

Make up a few similar questions of your own. Impress your friends by giving them a calculator and 'predicting' what will happen!

This GeoGebra file allows you to see how Alison's representation changes as the consecutive numbers increase. Move the slider to change the numbers.

Barbora from Parklane International School in the Czech Republic wrote about the patterns in the numbers:

I have noticed that the product of the middle pair is always 2 larger than the product of the outer pair. I have also noticed that the sum of the 1st and 4th number is equal to the sum of the 2nd and 3rd number. Furthermore, the 3rd number is always 2 larger than the 1st number and the 4th number is always 2 larger than the 2nd number. I think that these things will always happen because the numbers are arranged in the same order each time, so there isn't any variation in the pattern other than the integers used. The pattern is always: $n, n + 1, n + 2, n + 3$

Lyle, Caden and Michael from Cockburn Laurence Calvert Academy used Barbora's idea to explain what happens to the products. This is Lyle's work:

4 consecutive numbers | Multiply first and last numbers | Multiply middle pair | Notes |

1, 2, 3, 4 | 1 $\times$ 4 = 4 | 2 $\times$ 3 = 6 | difference of 2 |

2, 3, 4, 5 | 2 $\times$ 5 = 10 | 3 $\times$ 4 = 12 | difference of 2 |

10, 11, 12, 13 | 10 $\times$ 13 = 130 | 11 $\times$ 12 = 132 | difference of 2 |

1000, 1001, 1002, 1003 | 1000 $\times$ 1003 = 1003000 | 1001 $\times$ 1002 = 1003002 | difference of 2 |

Solution

$\begin{align}&n\hspace{3mm}\times \hspace{3mm}n+3&\hspace{15mm}&n+1\hspace{3mm}\times \hspace{3mm}n+2\\

&n^2+3n& &n^2+3n+2\end{align}$

Difference of 2

Ben from Comberton Village College in the UK, Andrew from Kellett in Hong Kong and Ella from Parklane International School also used the same algebra as Lyle. Andrew repeated the process for sets of 6 and 10 consecutive numbers (click on the image to open a larger version):

Matouš and Matyáš from Parklane International School in the Czech Republic wondered what the difference would be for other numbers of consecutive numbers, like 154. Here is their work:

For any number of consecutive numbers:*$x$ = total number of consecutive numbers$y$ = the difference between the two products (1st $\times$ last and 2nd $\times$ penultimate)*

Eg. If we use all the consecutive numbers between and including 1 and 154.

$x$ = 154

1 $\times$ 154 = 154 (

*1st $\times$ last*)

2 $\times$ 153 = 306 (

*2nd $\times$ penultimate*)

$y$ = 306 $−$ 154 = 152

*Have they made any assumptions?*

Freya from Comberton Village College applied the same method to numbers that are not consecutive, but go up in threes:

The sequence I chose goes up in threes. For my example, I used 2,5,8,11.

Outer pair: 2$\times$11=22

Inner pair: 5$\times$8=40

40$-$22=18

To explain this, I used algebra.

$n(n+9)=n^2+9n$

$(n+3)(n+6)=n^2+9n+18$

$(n^2+9n+18)-(n^2+9n)=18$

Imaan from Walton High School in England investigated several different numbers of numbers and distances between the numbers. Here is Imaan's work (click on the image to open a larger version):

Sophia and Bianca from Kellet and Jackson from Cockburn Laurence Calvert Academy tried out different differences between the numbers in a systematic way. This is Jackson's work, which includes a graph (click on the image to open a larger version):

Alain, Teodor and Fabian from Parklane International School and Andrew Chambers's students at British International School Phuket in Thailand both wrote up lots of ideas, rules and proofs - including things which could be used to explain the shape of Jackson's graph. The British International School Phuket students really enjoyed this task and spent 2 full lessons working on it. They worked out the difference between the products of the first and last and the the middle two numbers, rather than the first and last and the second and penultimate numbers:

Click here to see the British International School Phuket students' work, and click here to see Alain, Teodor and Fabian's work. Both also include explorations of when the numbers are all even, or all odd.

Venya from the British International School Phuket considered a very general case, where there are $n$ numbers that go up in steps of $q$:

Zara from St James Senior Girls School carried out a slightly different investigation into whether the products were even or odd (click on the image to open a larger version).

### Why do this problem?

This problem provides a purpose for practising the routine algebraic procedure of expanding brackets.

### Possible approach

*The inner pair product is always two more than the product of the outer pair.*

### Key question

Is there a way to represent the pair products that will explain the patterns you noticed?

### Possible support

This problem could also be approached purely numerically, as an exercise in developing fluency with multiplication tables while looking for pattern and structure.