Solution

160721

First name
Edward
School
Aquinas College
Country
Age
0

1. If rover is a dog, he isn't a cat. If rover's not a cat there is a lot of other things he could be
2. If 2n-m<0 then m is bigger then rearranged 2n<m, therefore n<m
It can't be the other way round as n<m, we don't know that 2n<m
3. If n>1, then it is bigger than n>0
4. If n+m is odd and both integers are positive it means that n-m is not zero, as it as 0 is even, and in order for n+m to be odd, an odd+even=odd an odd-even=odd
It can't work both ways, as if n-m is not zero it doesn't need to add to make an odd, as n-m is not zero it doesn't discount them adding to be even
5. n is even, n+1 is odd. even+odd=odd. It is reversible as an odd-odd=even
6. If n is bigger than m, then n-m will be bigger than 0 as n>m rearranges to n-m>0
It is reversible as n-m>0 can be rearranged to make n>m
7. As n is a positive integer, if n^2 is odd then n must be odd. Similarly, if n is odd then n^2 is odd. As oddxodd=odd
8. If n>2 then n^3 will be greater than 5n as n has to be an integer
The nearest integer after 2 is 3
3^3=27 which is greater than 5x3=15
It is reversible as if n^3>5n, n will be bigger than 2