SO we first (as the question stated) found the areas of parallelograms A - H.
The areas were as such:
A :16T
B :24T
C :24T
D :4T
E :16T
F :18T
G :8T
H :12T
Within these areas we found many interesting... findings, but before we proceed, let me tell you that F was a common exception.
1. We found that 2T equal to a small parallelogram.
You will see this if you draw out the isometric graph and draw 2 triangles equal to T. And it doesn't matter how you place them as long as they are next to each other.
2. This needs to be explained with a diagram.
16 24 24 - The first three areas
4 16 18 - The second group of three areas
8 12 _ - The last group, and on this will be the 'investigation'
Let's see the first two rows and their differences.
16 - 4 = 12
24 - 16 = 8
24 - 18 = 6
So those are the differences. Then inspect the second row with the first two of the third row.
8 - 4 = 4
16 - 12 = 4
Did you notice? 12 to 4 is divided by 3, 8 to 4 is divided by 2 so to find the next numeral, you do 6 divided by 1 which is a difference of 6 which makes 18 - 6 = 12.
3. The length and the height for all parallelograms multiply to half the area.