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3) The answer is always the sum of the digits timesed together. AxA-bxb=2b+2a if a-b=2.
4)
n(n+1)−(n−1)(n+2)=2
(n+1)(n+2)−n(n+3)=2
(n−3)(n−2)−(n−4)(n−1)=2
5) (n-1)(n+1)= n^(2)-1, so (n-1)(n+1)+1=n^(2).
6) let's take 4,5&6 4x5=20 and 6x5= 30. Add the two together you get 50. Let's call 4,5&6 A,b&c. A*b+A*c=A*(b+c) is the algebraic form of this or you could say 2(b)^(2) if the numbers are the same difference apart from b.