Solution

152907

First name
Ryan Johnson
School
British International School Shanghai Puxi
Country
Age
13

Let's call the first sequence number 1.
If you count up the squares of each one you get 8 when n=1, 16 when n=2, 24 when n=3 and so on. The difference between each number is 8 and the expression is 8n.

The second sequence is number 2. If you count up the squares you 8,24,48... When n=1,n=2,n=3... Respectively. The difference between these numbers is 16,24.
The difference between these is 8. So it's a quadratic sequence.
You half the number to get 4.
So the expression starts with 4n^2.
But when n=1 that only equals to 4 so you add 4.
So the expression is 4n^2+4. But that only works for the first one and not for the second or the third. So you have to times the 4 by n.
So the expression is 4n^2 +4n. That works for all the numbers.

The relationship between the sequence 1 and sequence 2 is that when n=1 in sequence 1 the nth termis 8 because the expression is 8n
You times that all by (0.5n+0.5) when n=1. This is because if you divide n=1 in sequence 2 by n=1 in sequence 1 you get 1. 8 divided by 8 is 1.
You do the same for n=2 and the others.
Then you get the sequence 1,1.5,2,2.5 and so on.
The expression for this is 0.5n+0.5.
That is why you times the number by (0.5n+0.5).
So 8*0.5 plus 8*0.5. This gives you 8. Which is the same as n=1 in the sequence 2.

A more simple solution is when n=3 in the sequence 2 it is equal to n=3 + n=2 + n=1 in sequence 1.
To prove it, n=3 in sequence 3 gets you 48 which is equal to 8+16+24.

Written By Ryan Johnson and Eddie Chan.