Solution

25238

First name
Sam
School
Lawrence Sheriff
Country
Age
16

At 8000 m above sea-level (mount-Everest), and assuming that our distance from the earth equates to its radius, 6378100. Then the ratio between its weight at sea level and that on a mountain is :

R(0) (sea-level) = 6378100 m ; 6378.1 km
R(1) (Mountain) = 6386100 m
r = [R(0)/R(1)]

W(1) (Mountain) = W(0) * r^2
= 0.9974961278 x W(0) ; W(0) (sea-level) = 200 N
= 199.4992 : 199.5 N

For W(1) = 0.049 N; (5 g on earth)
r^2 = 1/4096 so r = 1/64

Therefore, R(1) = 64 * R(0) = 408198400 m = 408198.4 km

which is 401820.3 km above sea-level, and you are also on the moon.