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I think that every sum with consecutive numbers that have a odd amount of numbers will add up to a number in that numbers timetable like for example 1+2+3=6 and 6 is in the same timetable as 3 and you can also find out what number you get from these consequtive number sums you can use a formulae 3x+3 for the 3 numbered sum so for the 1st number we can called x, the second number we can call x+1 and the 3rd nmber we can called x+2 so x+x+1+x+2=3x+3 so as you know 1 is equal to x you can replace x in the formula by the 1st number which here is 1 so (3x1)+3 which is 6 so you kow 1+2+3=6 so this formula roughly works for every formulae but the number have to change so for 5 consecutive number sum you would use 5x+10, so the #x is the number of numbers in this sum. If you can see it goes in a pattern so the pattern is 3x+3, 5x+10, 7x+21 so you can see that the patten for the 2nd number in the sum is times it by the placing of the number in the positive odd number line minus 1 so 7x+# could be found out by 7 is the 4th odd number-1 is 3 so 7x3=21 so the formulae for 7 numbers is 7x+21 and the logic is that what ever number you times by 7 you get an answer in the multiples of 7 and addig 21 you surely get a answer in the multiples of 7. There is a general formulae that will work for any consecutive sum with a odd number of numbers even 567 starting with 2 so using the formulae, B is the amount of the numbers in the sum which is 567 times x which is 2, the starting number + 283 as 567 is the 284th odd number -1 which is 283x567=160461 so (567x2)+160461=161595 which is 567x285.
My formula is (B numbers in sum)x + (Placing of B in odd numbers-1) x B= Answer.