For the first room we know that 3 dice on both sides would equal 21 so we took of eight which made 13 so that was the answer
For the second room we knew the key number was 13 so we added eight and five
then we had to add something to five to make 9 which was four next we had to add four to something to make eleven which was seven then we had to add seven to something to make sixteen which was nine
For the third room we worked out it was 2.5 away from each end then doubled 2.5 to get five because that was the other side of the middles and took five from nine because that was the whole thing which left four then square it then -1= 15so that was the answer
For the fourth room it was basicly trial and error so we made all the sides add up to the third key number which was 15.Top right was 7 top middle was 5 top left was 3 right middle was 2 middle left was 4 bottom right was 6 bottom middle 8 bottom left was 1 so add all the corner boxes would be 24 and minus 10 would be 14
the trays held 14 each and one was full so it was more than 14 and because of the statments we wrote out the three and four tables and it said in the four times tables it would be three more then one number in the four times table and one more than a number in the three times table and the number turned out to be 19 so that was the answer
the key number where 1=13 2=9 3=15 4=14 5=19 13th number in the alphabet is m the 9th is i the 15th is o the 14th is n the 19th is s which makes mions which is an anagram of Simon so that is his real name and the end of this problem