Skip to main content
### Number and algebra

### Geometry and measure

### Probability and statistics

### Working mathematically

### For younger learners

### Advanced mathematics

# Rationals Between...

Charlie and Alison are exploring fractions and surds.

They are looking for fractions with different denominators that lie between $\sqrt{65}$ and $\sqrt{67}$.

**Can you find some fractions that lie between $\sqrt{65}$ and $\sqrt{67}$?**

Charlie and Alison found that for some denominators, there is no fraction between $\sqrt{65}$ and $\sqrt{67}$. Click to reveal their thoughts.

**Charlie said:**

$\sqrt{65}$ is approximately $8.06$, and $\sqrt{67}$ is approximately $8.18$.

Fractions with a denominator of $4$ end in $0$ or $.25$ or $.5$ or $.75$ so there is no fraction with a denominator of $4$ between $\sqrt{65}$ and $\sqrt{67}$.

**Alison agreed with Charlie but thought about it in a slightly different way:**

I'm looking for a fraction $\frac{p}{q}$ where $\sqrt{65}<\frac{p}{q}<\sqrt{67}$.

This means that $65<\frac{p^2}{q^2}<67$,

or $65q^2<{p^2}<67q^2$.

Suppose $q=4$.

$65\times16<{p^2}<67\times16$

$1040<{p^2}<1072$

$32^2=1024$, and $33^2=1089$, so there is no perfect square between $1040$ and $1072$.

Therefore, $q\neq4$, so there is no fraction with a denominator of $4$ between $\sqrt{65}$ and $\sqrt{67}$.

**Can you find other denominators where there is no fraction in the interval?**

**How will you know when you have found them all?**

Or search by topic

Age 14 to 16

Challenge Level

Charlie and Alison are exploring fractions and surds.

They are looking for fractions with different denominators that lie between $\sqrt{65}$ and $\sqrt{67}$.

Charlie and Alison found that for some denominators, there is no fraction between $\sqrt{65}$ and $\sqrt{67}$. Click to reveal their thoughts.

$\sqrt{65}$ is approximately $8.06$, and $\sqrt{67}$ is approximately $8.18$.

Fractions with a denominator of $4$ end in $0$ or $.25$ or $.5$ or $.75$ so there is no fraction with a denominator of $4$ between $\sqrt{65}$ and $\sqrt{67}$.

I'm looking for a fraction $\frac{p}{q}$ where $\sqrt{65}<\frac{p}{q}<\sqrt{67}$.

This means that $65<\frac{p^2}{q^2}<67$,

or $65q^2<{p^2}<67q^2$.

Suppose $q=4$.

$65\times16<{p^2}<67\times16$

$1040<{p^2}<1072$

$32^2=1024$, and $33^2=1089$, so there is no perfect square between $1040$ and $1072$.

Therefore, $q\neq4$, so there is no fraction with a denominator of $4$ between $\sqrt{65}$ and $\sqrt{67}$.