Flipping twisty matrices

Yiran from Guanghua Qidi in China chose a shape and looked at its image under matrices of the form  $ \left( $$\begin{array}{cc}0& b\\ c& 0\end{array}$$ \right) $ where $b$ and $c$ can take the values $1$ and $-1.$ This is Yiran's work (click on the image to open a larger version). Note that for $b=1, c=-1$ the rotation is actually clockwise, not anticlockwise - as shown in Yiran's diagram.

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Andrei from School No. 205, Bucharest, Romania considered matrices of the form  $ \left( $$\begin{array}{cc}a& 0\\ 0& d\end{array}$$ \right) $ where $a$ and $d$ can take the values $1$ and $-1.$ Andrei also looked at more general points under both families of matrices. This is Andrei's work:

1. $b = c = 0,\ a = d = -1$ $$\left(\begin{array}{cc}-1& 0\\ 0& -1\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}-x\\ -y\end{array}\right).$$ This means each point (x, y) transforms into its symmetrical image with respect to the origin, i.e. into the point (-x, -y). This is a rotation of 180 degrees about the origin.

2. $b = c = 0,\ a = - 1,\ d = 1$ $$\left(\begin{array}{cc}-1& 0\\ 0& 1\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}-x\\ y\end{array}\right).$$ Here, it is a reflection in the y-axis.

3. $b = c = 0,\ a = d = 1$ $$\left(\begin{array}{cc}1& 0\\ 0& 1\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}x\\ y\end{array}\right).$$ In this situation each point transforms into itself.

4. $b = c = 0,\ a = 1,\ d = -1$ $$\left(\begin{array}{cc}1& 0\\ 0& -1\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}x\\ -y\end{array}\right).$$ This transformation leaves the abscissa unchanged and modifies the sign of the ordinate, being a reflection in the x-axis.

Now, I look at the next set of transformations.

5. $a = d = 0,\ b = c = 1$ $$\left(\begin{array}{cc}0& 1\\ 1& 0\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}y\\ x\end{array}\right).$$ In this transformation, the abscissa and the ordinate are interchanged, the transformation being a reflection in respect to the line $y=x$, the angle bisector of the first quadrant.

6. $a = d = 0,\ b = 1,\ c = -1$ $$\left(\begin{array}{cc}0& 1\\ -1& 0\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}y\\ -x\end{array}\right).$$

Andrei also concluded that this is a rotation of $90^\circ$ clockwise about the origin.

7. $a = d = 0,\ b = c = -1$ $$\left(\begin{array}{cc}0& -1\\ -1& 0\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}-y\\ -x\end{array}\right).$$ This corresponds to a reflection in the line $y=-x$.

8. $a = d = 0,\ b = -1,\ c = 1$ $$\left(\begin{array}{cc}0& -1\\ 1& 0\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}-y\\ x\end{array}\right).$$ This corresponds to a rotation of the point by 90 degrees anti-clockwise about the origin.