problem
Upsetting Pythagoras
Find the smallest integer solution to the equation 1/x^2 + 1/y^2 = 1/z^2
Find the smallest integer solution to the equation 1/x^2 + 1/y^2 = 1/z^2
If the last four digits of my phone number are placed in front of the remaining three you get one more than twice my number! What is it?