Solution

Connecting Averages Raniera

Problem / game
Connecting averages Back to problem
First name
Raniera
School
Flaxmere primary school
Country
New Zealand
Age
12

The exact y to x is Exponents: \(2^3 = 2 \times 2 \times 2 = 8\)

  • Negative Exponents: \(y^{-x} = \frac{1}{y^x}\)
  • Fractional Exponents: \(y^{\frac{1}{x}} = \sqrt[x]{y}\) because half of \(2^3 = 2 \times 2 \times 2 = 8\) is 2^2=4 because it has the ability to half it