Solution

37722

Problem / game
First name
Tim Coulter
School
William Farr
Age
15

999¬1000 --- 1000¬999
*1000
1000*999¬1000 --- 1000¬1000
root 1000
root 1000(1000)*999 --- 1000
if the root 1000 of 1000 > 1000/999 then 999¬1000 < 1000¬999
1000/999= 1.001001001...
root 1000 of 1000= 1.006...
therefore 1.006*999>1000
and that means 999¬1000>1000¬999

¬ is to the power of