in Mr Robison's extra tuition group, we have explored this problem and worked systematically. We found that square could not be 1 or 3 as square would reoccur or be to big, so it would have to be 2. We already knew that square was 2, so square squared is 4. Therefore oval is 4. 4x2=8 so semicircle is 8. We estimated that rectangle would be between 4 and 2 so it was 3. When we explored further, we found that triangle is 6 and circle is 12. In both sentences with inverse (upside down) triangle, the answer was inverse triangle so inverse triangle is 0. In both sentences with rhombus, the answer was the shape that wasn't the rhombus so rhombus is 1. Rectangle is 3 and 3x3 is 9. we predicted star=5 so 2x5=10 and hexagon is 10.
Inverse triangle =0
Rhombus = 1
Purple Square = 2
Rectangle = 3
Oval = 4
Star = 5
Triangle = 6
Semi circle = 8
Double star = 9
Hexagon = 10
Circle = 12
We found that 11 and 7 couldn't be in there as 11x2=22 and 22 is too great. 7x2=14 and 14 is too great. They are both prime so can't be included.