Problem
First name
Chris E-M
School
rastrick high school
Country
Age
15
if: ab=1,bc=2,cd=3,de=4 and ea=6
then 1*2*3*4*6=ab*bc*cd*de*ea -> 144=aabbccddee=(abcde)^2
square root both sides
12=abcde
a=12/bcde since ab=1 a=1/b
12/bcde = 1/b -Cross multiply-> 12b = 1bcde therefore cde=12
c=12/de also cd=3 so c=3/d
3/d=12/de -Cross multiply-> 3de=12d -> de=4d therefore e=4
since e = 4 and ea=6 -> 4a=6 so a=1.5
since a=1.5 and ab=1 -> 1.5b=1 so b=2/3
since b=2/3 and bc=2 -> (2/3)c=2 so c=3
since c=3 and cd=3 -> 3d=3 so d=1
a=1.5; b=2/3; c=3; d=1; e=4