Solution

153127

Problem
Which parabola? Back to problem
First name
Isobel Anderson
School
Wycombe High School
Country
England
Age
17

A: y=–(–(x+12)²+12(x+12)–36)
B: y=–((x+12)²–12(x+12)+27)
C: y=–(x+12)²+12(x+12)–36
D: y=(x+12)²–12(x+12)+27
E: y=–((x+6)²–12(x+6)+27)
F: y=–(–(x+6)²+12(x+6)–36)
G: y=–(x+6)²+12(x+6)–36
H: y=(x+6)²–12(x+6)+27
I: y=–(x²–12x+27)
J: –y=–x²+12x–36
K: y=–x²+12x–36
L: y=x²–12x+27