Diagonal Touch
Weekly Problem 21 - 2012
Two rectangles are drawn in a rectangle. What fraction of the rectangle is shaded?
Two rectangles are drawn in a rectangle. What fraction of the rectangle is shaded?
Image
![Diagonal Touch Diagonal Touch](/sites/default/files/styles/large/public/thumbnails/content-id-2448-Diagonal%252520touch%252520Stefania.png?itok=9BIWHZW9)
What fraction of rectangle $PQRS$ is shaded?
Image
![Diagonal Touch Diagonal Touch](/sites/default/files/styles/large/public/thumbnails/content-id-2448-Diagonal%252520touch%252520sol%252520Stefania.png?itok=17sEDOjL)
$\frac{16}{81}$ is shaded.
Let $x$ and $y$ be the distances shown. Then the shaded area is $8y + x$. But there are a number of similar triangles and from one pair $${x\over8} = {y\over1}$$ i.e. $$x = 8y$$ So, $$\frac{\mbox{shaded area}}{\mbox{total area}} = \frac{8y + x}{9(x + y)} = \frac{8y + 8y}{9 \times 9y} = \frac{16}{81}$$