Solution

Unequal Averages Tristan

First name
Tristan
School
Twyford School
School's Twitter handle
@TwyfordSchool
Age
10

In my opinion the best way to solve this problem is to use 2 odds and 3 evens

For example for

Median is greater than mode and mean is greater median

10 10 11 10 29 because it would be 

10=mode 11 = median and 14=mean

For mode < mean< median

For example 

11675

It would be 

Mode=1 mean=4 median 5

How  make this work is if i want the mode  to be low i put two low numbers in and to make it high i put to high numbers in.

For mean i put 3 high numbers then a medium then a low one to keep it not too small but not too big.

For the median if you wanted it to be the lowest you'd need 3 really close numbers that are low and 2 really high numbers  and for highest  numbers you must have 2 low numbers and three high numbers.

And for median< mode<mean

8,6,6,7,12

mode =6 median=7 mean =7.8