Using image 1, I formed the equations:
3x + y = 30
2x + 2y = 28
where x is the square
and y is the triangle
Using the method of elimination in simultaneous equations, I deduced that:
1 square is worth 8
1 triangle is worth 6
Using this and the information from row 3, I also found out the value of one circle, as:
the sum of three circles and one triangle is equal to 18.
Therefore, I deduced that one circle is equal to 4
Using the value of a square and the information provided in row 2, I found the value of one hexagon, as:
The sum of two squares and two hexagons is equal to 30
Therefore, I deduced that 1 hexagon is equal to 7
The column with the unknown value consists of two circles, one square and one hexagon. Therefore:
2(4) + 1(7) + 1(8) = ?
8 + 7 + 8 = ?
= 23
Therefore, the value of the unknown column is 23