Number crunch
Create 24 numbers from four digits. Why is 101 always a factor of their sum?
Problem
If you choose any four different non-zero digits, you can arrange them to form 24 different four-digit numbers.
If you were to add these 24 numbers, your answer would be a multiple of 101.
Can you explain why?
This problem is taken from the UKMT Mathematical Challenges.
Student Solutions
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In each of the columns (ones, tens, hundreds, thousands), each of the digits will appear an equal proportion of the time.
$\therefore$ each column contains the same digits in a different order
(each column contains six $a$s, six $b$s, six $c$s and six $d$s)
The sum of the digits in each column is the same, say this sum is $s$ (where $s = 6a+6b+6c+6d$).
Sum $= s + 10s + 100s + 1000s$
$=11s + 1100s$
$=11s + 11s\times100$
$=11s\times101$ which is a multiple of $101$