Couples
In a certain community two thirds of the adult men are married to three quarters of the adult women. How many adults would there be in the smallest community of this type?
Problem
In a certain community two thirds of the adult men are married to three quarters of the adult women.
How many adults would there be in the smallest community of this type?
Getting Started
The number of married men is equal to the number of married women.
We know that two thirds of the adult men are married.
List how many men there could be, and how many of them would be married.
We know that three quarters of the adult women are married.
List how many women there could be, and how many of them would be married.
Student Solutions
Good solutions were received from Luke from St George's College, Ruth from Manchester High School for Girls, Daniel from Junction City High School, Max from Bishop Ramsey C of E Secondary School and Rohan from Long Bay Primary.
Luke wrote:
Since two thirds of the adult men are married, the total number of men must be a multiple of 3.
Possible totals are:
| Total Men | Total Married Men |
| 3 | 2 |
| 6 | 4 |
| 9 | 6 |
| 12 | 8 |
Since three quarters of the adult women are married, the total number of women must be a multiple of 4.
Possible totals are:
| Total Women | Total Married Women |
| 4 | 3 |
| 8 | 6 |
| 12 | 9 |
| 16 | 12 |
Ruth wrote:
There are $m$ men and $w$ women in the community. $\frac{2}{3}$ of the men and $\frac{3}{4}$ of the women are married and there must be the same number of married men as married women, so \begin{eqnarray} \frac{2}{3}m &=& \frac{3}{4}w \\ 8m &=& 9w \end{eqnarray} Now $m$ and $w$ are both integers so the smallest solution to this equation is $$m = 9 , w = 8 $$so there are 17 people in the community, and 6 married couples.
There are other solutions gained by multiplying all the numbers by a constant for example you can double them all to get 18 men, 16 women and 12 married couples but 9 men and 8 women is the smallest solution.
Max wrote: