$UK$ means $10U + K$ and $SMC$ means $100S + 10M + C$, so we have
$$10U+K+4=100S+10M+C$$ The left hand side is at most $$ 10 \times 9
+ 8 + 4 = 102$$ so $$100S+10M+C \leq 102$$ Therefore $S \leq 1$, so
$S=1$ (since it can't be zero). So $$10M+C \leq2$$ So $M=0$
$M$ has the lowest value.
This problem is taken from the UKMT Mathematical Challenges.