Using index laws first
First, look at what is contained inside the brackets:$$\begin{split}5^x+5^x+5^x+5^x+5^x&=5\times5^x\\
&=5^1\times5^x\\
&=5^{1+x}\end{split}$$ So: $$\begin{split}5\left(5^x+5^x+5^x+5^x+5^x\right)^2&=5\left(5^{1+x}\right)^2\\
&=5\times5^{(1+x)\times2}\\
&=5^1\times5^{2+2x}\\
&=5^{1+2+2x}=5^{3+2x}\end{split}$$ So $5^{3+2x}=5^9$, which means $3+2x=9$, so $2x=6$, so $x=3$.