Two trains

Answer: $10$ hours and $15$ hours

Using ratio



Ratios $4 : k$ and $k : 9$ are equivalent $\Rightarrow k = 6$

(if $k=6$ isn't obvious you can get it from $\frac4k=\frac k9\Rightarrow k^2 = 4\times9$)

So journeys are $6+9$ and $6+4$ hours long.

Using fractions of the total journey times



The fraction of the journey that the red train completes in $k$ hours is the same as the fraction of the journey that the blue train completes in 4 hours.

$$\begin{array}{rl}{\displaystyle \frac{k}{k+9}}& ={\displaystyle \frac{4}{k+4}}\\ \Rightarrow k(k+4)& =4(k+9)\\ \Rightarrow k^2+4k& =4k+36\\ \Rightarrow k^2& =36\\ \Rightarrow k& =6\end{array}$$ So journeys are $6+9$ and $6+4$ hours long.

Using distance = speed $\times$ time

Suppose that the train from A to B travels at $a$ km per hour, and the train from B to A travels at $b$ km per hour. Then this diagram shows the distances travelled by each train in each part of the journey: So $k=6$, which means the journey from A to B is $15$ hours long, and the journey from B to A is $10$ hours long.