Ratio of areas
What is the ratio of the area of the hexagon to the area of the triangle?
Problem
What is the ratio of the area of a regular hexagon with side length 1 to that of an equilateral triangle of side length 4?
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![Ratio of areas Ratio of areas](/sites/default/files/styles/large/public/thumbnails/content-id-13754-ratio%252520of%252520areas%252520diagram.png?itok=SYkOj1DE)
This problem is taken from the World Mathematics Championships
Student Solutions
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![Ratio of areas Ratio of areas](/sites/default/files/styles/large/public/thumbnails/content-id-13754-hexagon%252520into%252520triangles.png?itok=xYCzWGP5)
If you draw lines from the centre of the hexagon to each of its vertices, 6 identical isosceles triangles are formed (with the green angles equal).
The blue angle is 360$^\circ\div$6 = 60$^\circ$, which means that the green angles must also be 60$^\circ$, and so the hexagon is split into 6 equilateral triangles - which have side length 1, the same as the hexagon.
Splitting both shapes into equilateral triangles with side length 1
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![Ratio of areas Ratio of areas](/sites/default/files/styles/large/public/thumbnails/content-id-13754-hexagon%252520as%252520triangles.png?itok=AKxvvdHb)
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![Ratio of areas Ratio of areas](/sites/default/files/styles/large/public/thumbnails/content-id-13754-triangle%252520into%2525204%252520triangles.png?itok=LzHKTM4w)
Joining the midpoints of the sides, as shown on the right, we can split the triangle into 4 equilateral triangles with side length 2.
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![Ratio of areas Ratio of areas](/sites/default/files/styles/large/public/thumbnails/content-id-13754-triangle%252520into%25252016%252520triangles.png?itok=yQFDDYHU)
Doing the same to each of the smaller triangles formed gives equilateral triangles with side length 1. There are 4$\times$4 = 16 of these in the large equilateral triangle.
So the hexagon contains 6 equilateral triangles of side length 1, whilst the triangle contains 16. So their areas are in the ratio 6:16, which simplifies to 3:8.
Scaling the hexagon up
6 copies of the triangle will fit together to make a hexagon with side length 4.
So 6 copies of the triangle will make a copy of the hexagon which has been enlarged by a scale factor of 4.
That means its area has been enlarged by a scale factor of 4$^2$ = 16.
So 6 copies of the triangle have the same area as 16 copies of the hexagon.
So the ratio of the area of the hexagon to the area of the triangle is 6:16, which simplifies to 3:8
So the hexagon contains 6 equilateral triangles of side length 1, whilst the triangle contains 16. So their areas are in the ratio 6:16, which simplifies to 3:8.
Scaling the hexagon up
Image
![Ratio of areas Ratio of areas](/sites/default/files/styles/large/public/thumbnails/content-id-13754-6%252520triangles.png?itok=YyGMnWRR)
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![Ratio of areas Ratio of areas](/sites/default/files/styles/large/public/thumbnails/content-id-13754-hexagon%252520as%252520triangles.png?itok=AKxvvdHb)
So 6 copies of the triangle will make a copy of the hexagon which has been enlarged by a scale factor of 4.
That means its area has been enlarged by a scale factor of 4$^2$ = 16.
So 6 copies of the triangle have the same area as 16 copies of the hexagon.
So the ratio of the area of the hexagon to the area of the triangle is 6:16, which simplifies to 3:8
Scaling the triangle down
Image
![Ratio of areas Ratio of areas](/sites/default/files/styles/large/public/thumbnails/content-id-13754-hexagon%252520as%252520triangles.png?itok=AKxvvdHb)
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![Ratio of areas Ratio of areas](/sites/default/files/styles/large/public/thumbnails/content-id-13754-triangle.png?itok=ZOCAqJfe)
This means that their area is 4$^2$ = 16 times smaller.
So, when scaled down by a factor of 16, the area of the triangle fits 6 times into the area of the hexagon. So the area of the hexagon is $\frac6{16}=\frac38$ of the area of the triangle.
So the ratio of the area of the hexagon to the area of the triangle is $\frac38$:1, which simplifies to 3:8.