Let the diameter of the smallest semicircle be $d$. Then $d$ is equal to one of the equal parts of AE, and the diameters of the other semicircles are $3d$ and $4d$, as shown below.

 

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Finding the lengths of the paths in terms of $d$

The upper path is half of the circumference of a full circle with diameter $4d$.

The circumference would $\pi\times4d=4\pi d$, so the length of the path is $2\pi d$.

The lower path is the distance around a semicircle with diameter $3d$ and the distance around a semicircle with diameter $d$.

The distance around the medium semicircle is $\frac12\pi\times3d=\frac32\pi d$.

The distance around the smallest semicircle is $\frac12\pi\times d=\frac{1}{2}\pi d$.

So the total length of the lower path is $\frac32\pi d+\frac12\pi d=\frac42\pi d=2\pi d$.

So the two paths are of equal length.

Considering formulae for lengths of semicircles

Both paths are made up of semicircles. The circumference of a circle is proportional to its diameter (multiply by $\pi$), so the distance around a semicircle is also proportional to the diameter (multiply by $\frac12\pi$).

So the length of the lower path is $\frac12\pi\times d+\frac12\pi\times 3d=\frac12\pi\times (3d+d)=\frac12\pi\times4d$. But that is equal to the length of the upper path! So the two paths are of equal length.

Will this work for other pairs of paths whose horizontal distance is equal?