Happy Octopus
Problem
Have you met Happy Numbers? Start with any number you like and form a sequence by writing down the sum of the squares of the digits of each number to get the next number in the sequence. For example, from 31 you go to 10 because 3 squared plus 1 squared makes 10. Here are some 'happy' sequences:
31 -> 10 -> 1 -> 1 -> 1 ...
68 -> 100 -> 1 -> 1 -> 1 ...
25 -> 29 -> 85 -> 89 -> 145 -> 42 -> 20 -> 4 -> 16 -> 37 -> 58 -> 89 ->...
122 -> 9 -> 81 -> 65 -> 61 -> 37 ->...
1122 -> 10 -> 1 -> 1 ;...
Numbers are called 'happy' when their sequences, sooner or later, give repeated 1's. We say 1 is a fixed point. The numbers 31, 68 and 1122 are happy and so are the numbers 10 and 100.
The number 25 is sad because, however long we go on with the sequence, it will never come to 1, it will just keep repeating the terms (89, 145, 42, 20, 4, 16, 37, 58) over and over again. We call this an 8-cycle or loop. Can you see why 122 is also a sad number? Can you find some more happy numbers?
This investigation is about happy numbers in the World of the Octopus where all numbers are written in base 8. Octi the octopus counts:
1, 2, 3, 4, 5, 6, 7, 10, 11, 12, 13, 14, 15, 16, 17, 20, 21, 22, 23, 24, 25 ... and so on.
In base 8 the number "one-zero" (written 10) means eight, the number "one-one" means nine etc. and the number "two-zero" (written 20) means two eights or sixteen in base 10. Here are two 'happy' sequences with all numbers written in base 8:
24 -> 24 -> 24 -> 24 -> 24 -> ...
31 -> 12 -> 5-> 31 -> 12 -> 5 ...
We found that twenty, in base 10, that is two-four in base 8, was a sad number. Octi would call two-four a 'happy number' because its sequence 'homes in' on the repeated term (or fixed point) 24.
Three-one, in base 8, is twenty five in base ten; one-two in base 8 is ten in base ten. So, from the sequence above, we can see that three-one, one-two and five are all sad numbers.
Find all the fixed points and cycles for the happy number sequences in base 8.
Student Solutions
B | a |
1 x 0 = 0 | 7 x 1 = 7 |
2 x 1 = 2 | 6 x 2 = 12 |
3 x 2 = 6 | 5 x 3 = 15 |
4 x 3 = 12 | 4 x 4 = 16 |
5 x 4 = 20 | |
6 x 5 = 30 | |
7 x 6 = 42 |
The only possibilities are $a = 2, \ b = 4$ and $a = 6, \ b = 4$.
With more digits the sums of squares are never bigger than some multiple of $7^2$. It can be proved that sequences cannot go on for ever without repeating patterns and so all sequences go into cycles or go to a fixed point. Moreover it can be proved that there are no fixed points with 3 or more digits.