The sum of all $64$ numbers is their mean times the number of numbers, which is $$64 \times 64 = 4096$$

Similarly the sum of the first $36$ numbers is $$36 \times 36 = 1296$$

Therefore the sum of the last $28$ numbers is $$4096 - 1296 = 2800$$

Therefore the mean of the last $28$ numbers is $$\frac{2800}{28}=100$$

This problem is taken from the UKMT Mathematical Challenges.

You can find more short problems, arranged by curriculum topic, in our short problems collection.