You may also like

problem icon

Enclosing Squares

Can you find sets of sloping lines that enclose a square?

problem icon

Parallel Lines

How does the position of the line affect the equation of the line? What can you say about the equations of parallel lines?

problem icon

Graphical Triangle

Weekly Problem 35 - 2007
What is the area of the triangle formed by these three lines?

Translating Lines

Stage: 3 Challenge Level: Challenge Level:1

Jiwon Jung noticed:

You can tell it's translated because the gradient hasn't changed, and the pairs of lines are parallel.

Ellie from Chiswick expanded and gave reasoning;

I experiemented with the lines and translations. I noticed that if you just translate up and down (in the $y$ direction) then the constant goes up or down the same number of places as the left has moved.
If you move sideways, then it is in proportion to the gradient of the line.

I made this into a formula.
If the original line is $y=ax+b$, and we move $X$ right and $Y$ up, then the new line is $y=ax+b-aX+Y$. So the constant becomes $b-aX+Y$.
So the constant is the same, but minus the gradient times the movement (if you move left then $X$ is negative), and then plus the vertical movement (of you move down then $Y$ is negative).

So the pairs are:

So lots of values of $X$ and $Y$ will make these work, as you can make equations that describe the motion, and then any solutions will work. You could even plot the solutions, they themselves would be straight line graphs.
So for $y=2x+1$ translated to $y=2x-4$, the $X$ and $Y$ motion satisfies $1-2X+Y=-4$ by the equation above, so any $X,Y$ satisfying $Y-2X=-5$ will do the translation above.