We had good solutions from Andrei in Bucharest, and from Matt and Andrew at the Perse School
The solution in the first case is $x = 2, y = 1$ and in the second case is $x = - 199998, y = 199999.$
For the first two lines one gradient is a little under minus one and the other gradient a little over.
For the second two lines both gradients are a little above minus one.
All four lines cut the $y$-axis very near to $3$.
Because the pairs of lines in each case are nearly parallel the slight and unique change in each line's gradient away from minus one causes the intersection to occur in very different places.