Or search by topic
Use this proof sorter to construct a proof that it is impossible to find a cubic equation which passes through $(0,0)$ and has turning points at $(1,2)$ and $(2,1)$. This particular type of proof is called a proof by contradiction.
There are several different correct arrangements of these statements. Once you have had a go at rearranging the statements you can compare your answer to the possible solution which can be seen at the bottom of the page by clicking on the "Show Possible Solution" button.
See Curve Fitter for the problem that this proof sorter relates to.