Solution

153437

First name
Samuel Gregg
School
Wellington School
Country
Age
15
Email address
samdgregg@gmail.com

1. Use the general form y=mx+c, to solve for the equation simultaneously.
We know y=3 when x=2 and y=8 when x=8
3=mx+c
8=8m+c
m=5/6, c=4/3, therefore equation of line is y=5x/6+(4/3)
When x=4, y(a)=14/3
Therefore a=14/3

2. Work out gradient joining two known points, 5/11.
Use (y-y(1))=m(x-x(1))
Using this, we derive
11y=5x+63
When y=10, x=9.4
Therefore b=9.4

3.Using the same equation as a above, we derive that 4.8y=26x+71When x=7.3,
4.8y=260.8
y=163/3, 54.3 recurring
Therefore c=163/3

4. Using the same method as before, we derive
y=28x/5-1057/25
Solving for x when y=47.5, x=16.03214286
Therefore=16.03(2d.p)

5. Using the same method as before, we derive,
y=-19x/9+332/9
When x=12, y=104/9
Therefore, e=104/9