Homely angles
Weekly Problem 18 - 2011
Draw an equilateral triangle onto one side of a square. Can you work out one particular angle?
Draw an equilateral triangle onto one side of a square. Can you work out one particular angle?
Problem
A square is labelled anticlockwise ABCD.The point E is outside the square so that CDE is an equilateral triangle. Find angle BED.
Student Solutions
Since ABCD is a square, $\angle BCD = 90^{\circ}$,
and since CDE is an equilateral triangle, $\angle DCE = 60 ^{\circ}$.
Thus $\angle BCE = \angle BCD + \angle DCE = 90^{\circ}+60^{\circ}=150^{\circ}$.
Because CDE is an equilateral triangle, $EC = DC$ and also, because ABCD is a square, $DC = CB$. Hence $EC = CB$ and ECB is an isosceles triangle.
So $\angle CEB = \angle CBE = \frac{1}{2} (180-150)^{\circ} = 15^{\circ}$, and hence $\angle BED = \angle CED-\angle CEB = 60^{\circ} - 15^{\circ} = 45 ^{\circ}$.
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