Solution

156701

First name
Emily Tucker
School
Burford, Marlow Bottom
Country
Age
10
Email address
em14tucker@hotmail.com

The first problem required logic. I knew that the threes could fit around the ones' sequence. That only left two twos. I placed a two in between the ones - as the middle number. Then I could only experiment with the remaining card - a two. I tried the two in every possible place and came out with two sequences- 231213 and 312132.

The second problem required more then just logic. I used the aid of the interactivity for this problem. I knew that the ones' and twos' sequence could fit inside the fours. I tried that, but it didn't work as the ones and twos overlapped other numbers. I slid the ones beside the fours, then I put the twos in the possible places - only one worked. The gaps left were three spaces apart - perfect for the threes. I came out with the sequence- 41312432

The third problem was a bit of a mind teaser. Luckily, I had spotted a pattern - all the sequences started with the highest number, followed by a one. I put the seven and the one in these places and then I examined the sequences again . The sequences had a three in between the ones! I slotted the threes in the middle of the ones. I thought about the problem. I realised that the highest numbers would be early in the sequence, as they required more space in between them. The highest number left was six. I placed the sixes in the next possible place. Then I dealt with the fives. I slotted them in next to the sixes, but the last five and last six required the same space. So, I tried the next available space for the fives and it fitted. The next challenge was the fours. I did what I did for the last numbers. I placed the fours in the first available space - luckily it fitted. That left two spaces, two spaces apart . I slotted the only remaining cards in the remaining spaces - the twos. Finally , I had the sequence - 71316435724625.