Problem
First name
Ryan
School
St Philips CfE Primary School
Country
Age
11
Solution for number 3
I have noticed that the sum of 4 consecutive Fibonacci numbers is equal to the numbers before and after the last number.
e.g. 1,1,2,3,5,8,13,21
1+1+2+3=7
2+5=7
3+5+8+13=29
8+21=29