The first question is 2 5 2, because 2 plus 2 is 4 plus 5 which is 9, divided by three, because there are 3 numbers. That gets you 3 which is the mean and 2 two's which is the mode.
The second question is 10 1 10, because the mean was 3 and the mode was 10. So you put 2 tens plus one because 7 times 3 is 21.
The third question is 3 10 11, because eight was the mean so you times it by 3 (the amount of numbers)that gets you 24. But the median was 10 and the range was 8 so you have to put 3 and 11.
The fourth question is 6 6 8 9 ,because the amount of numbers (four) times by the mean (7.5) is 30. But the mode was 6 so you had to put 2 sixes. The median was seven so the two middle numbers have to have seven in the middle.
The fifth question is 0 6 7 11, because the mean (six) times by the amount of numbers (four) is 24. The median was 6.5 so you have to put 6 and 7. The range was 11 and you already had 13 (6 plus 7). So if you put 11 and 0 the range and number will be right.
The sixth question is 1 2 3 3 11, because the mean (four) times the amount of numbers (five) is 20. The range is 9 and the mode is 3 so you have to put two threes. Same for the other solution 0 3 3 5 9.
The seventh question is 2 2 3 5 8, because the mean (four) times the amount of numbers (five) is 20. But the range is 6 and the mode is 2. So you put 2 twos and you put the range up to 8. Which means you have to start with 2. Same for the other solution 1 3 3 6 7.
The eight question is 1 7 7 9 11, because the mean (seven) times the amount of numbers (five) is 35. The mode is 7 so you have to put two sevens. Also the range is 10 so if you start with 1 you have to put 11. Same as the other solutions 3 5 7 7 13 and o 7 7 9 10.
Extension
The first question is no, because the mean and the amount of numbers times up to 16. With the mode 1 you have to put two ones but because the range is 10 if you put one the last number has to be ten. But also there is the median of 2 which makes it impossible.
The second question is no, because of the range and median of 10 and 2 it is impossible.
The third question is no, because of the mean, mode and median of 4 1 2 it is impossible.
The fourth question is no, because you can't put negative numbers and positive would be impossible because
of the range of ten. If the mode is one and the median 2 there will be alot of zero's which wold beat the mode of two.