Skip to main content
### Number and algebra

### Geometry and measure

### Probability and statistics

### Working mathematically

### For younger learners

### Advanced mathematics

# Card Trick 2

## You may also like

### Painting Cubes

### Cube Paths

### How Many Dice?

Links to the University of Cambridge website
Links to the NRICH website Home page

Nurturing young mathematicians: teacher webinars

30 April (Primary), 1 May (Secondary)

30 April (Primary), 1 May (Secondary)

Or search by topic

Age 11 to 14

Challenge Level

- Problem
- Student Solutions

You may have found that this trick does not work if the fourth card from the bottom is the same numerical value and colour as one of the 3 chosen cards or as the first, second or third card from the bottom, a probability of 6/45. When the 'magician' looks at the cards and sees that this has happened the best thing is to carry on with the trick but first to say that the cards should be shuffled again and give some convincing reason!

SUGGESTED SOLUTION

The card which the volunteer keeps will always be the fourth
card from the bottom of the pack which has the same numerical value
and colour as the predicting card. This is because, whatever 3
cards are selected by the volunteer, with these 3 cards and the
predicting card, 4 cards are removed from the pack. Then 45 cards
are counted out, and this leaves the last 3 cards to make up 52
altogether. Suppose the 3 cards selected have values *x* ,
*y* and *z* then the number of cards counted out is
(15 - *x* ) + (15 - *y* ) + (15 - *z* ) +
*x* + *y* + *z* = 45.

Correct solutions were sent in by:

**Sarah** - Archbishop Sancroft High School

Imagine you have six different colours of paint. You paint a cube using a different colour for each of the six faces. How many different cubes can be painted using the same set of six colours?

Given a 2 by 2 by 2 skeletal cube with one route `down' the cube. How many routes are there from A to B?

A standard die has the numbers 1, 2 and 3 are opposite 6, 5 and 4 respectively so that opposite faces add to 7? If you make standard dice by writing 1, 2, 3, 4, 5, 6 on blank cubes you will find there are 2 and only 2 different standard dice. Can you prove this ?