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Charlie summarises the solution as follows:
$\frac{1}{3}$ is $\frac{2}{24}$ or $\frac{1}{12}$ bigger than
$\frac{2}{8}$
$\frac{3}{4}$ is $\frac{1}{12}$ smaller than $\frac{5}{6}$
$\frac{1}{3}$ is $\frac{3}{6}$ or $\frac{1}{2}$ smaller than
$\frac{5}{6}$
$\frac{3}{4}$ of $\frac{2}{3} = \frac{3}{4}$ of $\frac{8}{12 }=
\frac{6}{12} = \frac{1}{2}$