#### You may also like ### Good Approximations

Solve quadratic equations and use continued fractions to find rational approximations to irrational numbers. ### Not Continued Fractions

Which rational numbers cannot be written in the form x + 1/(y + 1/z) where x, y and z are integers? ### Comparing Continued Fractions

Which of these continued fractions is bigger and why?

# There's a Limit

##### Age 14 to 18 Challenge Level:

Tony of State College Area High School, Pennsylvania, USA and Chi Kin of Saint Dominic's International School, Lisbon sent in excellent solutions and here is Chi Kin's:

What happens when successive terms are taken in the continued fraction I calculated the first five terms

$2 + {3\over2} = {7\over2} = 3.5$

$2 + \frac{3}{2+{3\over2}} = {20\over7} = 2.86$

The third term is $3.05$

The fourth term is $2.95$

And the fifth term is $3.02$

Thus, when successive terms are taken, the results oscillate alternately above and below $3$.

Indeed, if the fraction goes on forever, we would get $3$.

Suppose the continued fraction is denoted as $F$. Thus

\eqalign{ F &=& 2 + \frac{3}{F} \\ F &=& \frac{2F + 3}{F} \\ F^2 - 2F - 3 &=& 0 \\ (F-3)(F+1) &=& 0.}

Thus $F = 3$, because $F$ cannot be negative.